import Foundation
let pattern = #"^((\d\d[2468][048]|\d\d[13579][26]|\d\d0[48]|[02468][048]00|[13579][26]00)-02-29|\d{4}-((0[13578]|1[02])-(0[1-9]|[12]\d|3[01])|(0[469]|11)-(0[1-9]|[12]\d|30)|(02)-(0[1-9]|1\d|2[0-8])))T([01]\d|2[0-3]):[0-5]\d:[0-5]\d\.\d{3}([+-]([01]\d|2[0-3]):[0-5]\d|Z)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
2023-02-28T00:00:00.000Z
2023-02-29T00:00:00.000Z
2024-02-29T00:00:00.000Z
2023-06-30T00:00:00.000Z
2023-06-31T00:00:00.000Z
2023-07-31T00:00:00.000Z
2023-07-31T00:00:00.000-05:30
2023-07-31T00:59:59.000Z
2023-07-31T00:60:59.000Z
2023-07-31T00:59:60.000Z
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression