import Foundation
let pattern = #"^NEM.[A-Z0-9]{3}.[A-Z0-9]{3,6}.[0-9]{3}.[0-9]{1,3}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
NEM.ESB.IPAB.400.001
NEM.ESB.IPAB.400.003
NEM.ESB.TST.400.1
NEM.BPM.TST.400.1
NEM.ESB.TSTTST.400.1
NEM.BPM.TSTTST.400.1
NEM.ESB.TST.400.001
NEM.BPM.TST.400.001
NEM.ESB.TSTTST.400.001
NEM.BPM.TSTTST.400.001
NEM.ESB.AAA.000.000
NEM.BPM.AAA.000.000
NEM.ESB.AAAAAA.000.000
NEM.BPM.AAAAAA.000.000
NEM.ESB.ZZZ.999.999
NEM.BPM.ZZZ.999.999
NEM.ESB.ZZZZZZ.999.999
NEM.BPM.ZZZZZZ.999.999
ANEM.ESB.TST.400.1
AEM.BPM.TST.400.1
AEM.ESB.TSTTST.400.1
AEM.BPM.TSTTST.400.1
AEM.ESB.TST.400.001
AEM.BPM.TST.400.001
AEM.ESB.TSTTST.400.001
AEM.BPM.TSTTST.400.001
AEM.ESB.AAA.000.000
AEM.BPM.AAA.000.000
AEM.ESB.AAAAAA.000.000
AEM.BPM.AAAAAA.000.000
AEM.ESB.ZZZ.999.999
AEM.BPM.ZZZ.999.999
AEM.ESB.ZZZZZZ.999.999
AEM.BPM.ZZZZZZ.999.999
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression