re = /([+0]?[06]?)(?&sep)(36)?(?&sep)(?P<aera>1|[2-9][0-9])(?&sep)(?P<num>\d{3})(?&sep)(\d{2})(?'sep'[\)\(-\/\.x ]*){2}/i
str = '+36 20 800 8848
36 1 267-5260
+36 1 267 5260
+36 24 415 351
06 (24) 415 351
6(1)415 3510
00361-267-5260
0036-1-267-5260
0036-1-267-52-60
208008848
20800 88-48
00 34 800 828
((06)|[\\+0]{0,2}\\s*36)
[+0]{0,2}(?&sep)36'
subst = '$3$4$5$6'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html