const regex = /^(?<street>(?!\d+ )[\p{L}\d'\u2018-\u2019]+\.?(?:[ -][\p{L}\d'\u2018-\u2019]+\.?)*(?<! \d+)),? (?<houseNumber>[1-9\p{L}][\d\p{L}]*(?:(?: | ?[\-/+,] ?)[\d\p{L}]+)*?)$/umg;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('^(?<street>(?!\\d+ )[\\p{L}\\d\'\\u2018-\\u2019]+\\.?(?:[ -][\\p{L}\\d\'\\u2018-\\u2019]+\\.?)*(?<! \\d+)),? (?<houseNumber>[1-9\\p{L}][\\d\\p{L}]*(?:(?: | ?[\\-\/+,] ?)[\\d\\p{L}]+)*?)$', 'umg')
const str = `Test-Straße 1
Chaussée de Tirlemont 373
Mühlenstraße 23
Straße des 17. Juni 135
4th Street 12ab
3rd Avenue 1435
Hamburger Str. 11-19
K4 12
Test-Str. 12ab
Test-Str. 12a-d
Test Str. 51 16
Test-Str. 17/18
Test Str. QA/3/31
Test Str. 51 / XX / 31`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions