import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = ##"{\s*{\s*#\s*(?<operator>endcase|endswitch|endfor|endif|if|elif|else|for|switch|case|default)\s*(?<args>[^}]*)\s*}\s*}\s*(?<body>[^{]*(?:\s*{\s*{\s*#\s*(?!(?&operator))\s*[^}]*\s*}\s*}\s*[^{]*)*)"##
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = ##"""
<div>
{{#if arg1.arg2}}
<span>{{#var arg3 static}}</span>
blablabla{{#for k, v in arg4}}
<p>{{#var k}}<span>{{#var v.arg5}}</span></p>
{{#if (k == "test" or v != 0) and k == 0}}
<span></span>
{{#elif k == 0}}
<p></p>
{{#else}}
<div></div>
{{#endif}}
{{#endfor}}
{{#endif}}
{{#switch arg6}}
{{#case 5}}
case 5
{{#case 6, 7, 8}}
case 6, 7, 8
{{#endcase}}
{{#default}}
def
{{#endcase}}
{{#endswitch}}
{{#for i as 0, 5}}
test i
{{#endfor}}
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression