import Foundation
let pattern = #"(?<!\.)(\b[a-zA-Z_]+[a-zA-Z0-9_]+)\.[a-zA-Z0-9_\.]+"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = ###"""
module.func()
module.class.func()
module.module.class . func()
__module__.module.class.func()
module.constant
module.class.constant
module.class.class.constant
module11.func()
modu123le.class.func()
modu123le.module.class.func()
modu123le.module123.class.func()
"1 if module11.func(col) == 'A' else 3"
"1 if module11.func(col) == 'A' else ( _module.constant == 'B') else 34"
"module.func()"
1.0
1module.func()
2module.class.func()
col.upper() ##No way to know whether col is a module
module . func() ##Need to remove spaces before and after .
module . class . func()
"""###
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression