import Foundation
let pattern = #"([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})([0-9a-fA-F]{2})"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
60060160d63036007ff161103ed5e311
60060160d6303600c659771b3ed5e311
60060160d630360089338aa421b1e311
60060160d6303600990f61b521b1e311
60060160d6303600367d84115d58e411
60060160d430360087eacc151270e411
60060160d63036008cf99f0240b1e311
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let substitutionString = #"\1:\2:\3:\4:\5:\6:\7:\8:\9:\10:\11:\12:\13:\14:\15:\16"#
let result = regex.stringByReplacingMatches(in: testString, range: stringRange, withTemplate: substitutionString)
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression