const regex = /@(.+?):/g;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('@(.+?):', 'g')
const str = `rainyear@hotmail.com:pepper
rajkomatt3@gmail.com:wehttam12
rakkasan240b@gmail.com:dn38416
rallytruckgnome@gmail.com:urban12
rammer388@gmail.com:ryanm08
ramonlopezjr@gmail.com:26may2001
ramsec@live.com:ramseywii1
randomhulu@gmail.com:moppel12
rangeman101@hotmail.co.uk:warcraft4
rangerkid1997@gmail.com:fetherolf5432
ranglinm@yahoo.com:rang94631
raphhashem@gmail.com:31951raph
rappe.austin@gmail.com:Elle4637096
ratof81@gmail.com:lovecraft1
raxarraxar@gmail.com:48oakao42
raylonlong@gmail.com:rayray12
rayvale.games@googlemail.com:fDbXh87Xfn
ray_2096@hotmail.com:hardys1996
rbenade@hotmail.ca:bandstra1
rcolegreco@gmail.com:Hell0W0rld
rdfenton@hotmail.com:scoots55
`;
const subst = `:`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions