re = /(^(0?[1-9]|[12][0-9]|3[01])\.(0?[1-9]|1[012])\.(19|20)\d\d( ([01]?[0-9]|2[0-3]):[0-5][0-9])?$|^\{ts \'((19|20)\d\d)\-(0?[1-9]|1[012])\-(0?[1-9]|[12][0-9]|3[01]) ([01]?[0-9]|2[0-3]):[0-5][0-9]:[0-5][0-9]\'\}$|^$)/
str = '30.12.2013'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html