# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"""
[[:blank:]]*+(?:[\[\(].*[\]\)][[:blank:]]*+)?(.*?)[[:blank:]\[\(]*+([1-2]\d{3}).*
"""
test_str = ("2 Fast 2 Furious [2003] [SD]\n"
"2 Fast 2 Furious (2003) [SD]\n"
"2 Fast 2 Furious ((2003) [SD]\n"
"A Goofy Movie (1995) (HD) (720p)\n"
"[test]A Goofy Movie (1995) (HD) (720p)\n"
"(test) A Goofy Movie (1995) (HD) (720p)\n"
"2 Fast 2 Furious 2003 \n"
" 2 Fast 2 Furious 2003\n"
"The Lion King 2- Simba's Pride (1998) (HD) (1080p)\n"
"The.Grand.Budapest.Hotel.2014.1080p.BluRay.x264-BLOW\n"
"Another.Earth.2011.LIMITED.720p.BluRay.X264-AMIABLE\n"
"The.Green.Mile.1999.720p.BluRay.x264-HDCLASSiCS\n"
"The Road 2009 Bluray DTS 720 p - TRiNiTY\n"
"Dead Poets Society (1989) 720p Blu-ray x264 DTS MSubs [DDR]\n"
"Garden.State.2004.720p.BluRay.X264-AMIABLE\n")
subst = "\\1 (\\2) \\3"
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0, re.MULTILINE | re.VERBOSE)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html