import Foundation
let pattern = #"(?<type>[A-Z]{1})(?<subtype>[A-Z<]{1})(?<issue_country>[A-Z]{3})(?<doc_number>[A-Z0-9<]{9})(?<check_sum>[0-9]{1})(?<first_optional>[A-Z0-9<]{15})\n(?<date_brith>[0-9]{6})(?<birth_check>[0-9{1}])(?<sex>[MF]{1})(?<expiration_date>[0-9]{6})(?<expiration_check>[0-9]{1})(?<nationality>[A-Z]{3})(?<second_optional>[A-Z0-9<]{11})(?<check_digit>[0-9]{1})\n(?<lname>[A-Z]+)(?<lname2><[A-Z]+){0,}<<(?<spacing>[<]{0,})(?<fname>[A-Z]+)(?<mname1><[A-Z]+){0,}(?<complement><.+){0,}"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
IDCHES0002068<8<<<<<<<<<<<<<<<
8102287F1301014CHE<<<<<<<<<<<4
VADIS<<QUO<<<<<<<<<<<<<<<<<<<<
I<NLDXI020DF236123456783<<<<<<
7208148F1108268NLD<<<<<<<<<<<9
VAN<DER<STEEN<<MARIANNE<LOUISE
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression