import Foundation
let pattern = ##"((?:[a-z0-9\.\-\+]*):\/\/(?:[^\s:@\/]+(?::[^\s:@\/]*)?@)?(?:(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)(?:\.(?:25[0-5]|2[0-4]\d|[0-1]?\d?\d)){3}|\[[0-9a-f:\.]+\]|([a-z_-_0-9](?:[a-z_-_0-9-]{0,61}[a-z_-_0-9])?(?:\.(?!-)[a-z_-_0-9-]{1,63}(?<!-))*\.(?!-)(?:[a-z_-_-]{2,63}|xn--[a-z0-9]{1,59})(?<!-)\.?|[a-z_-_0-9](?:[a-z_-_0-9-]{0,61}[a-z_-_0-9])?(?:\.(?!-)[a-z_-_0-9-]{1,63}(?<!-))*|localhost))(?::\d{2,5})?(?:[\/?#][^\s]*)?\Z)"##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"http://www.google.com"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression