re = /(0?[1-9]|[12][0-9]|3[01])\/(0?[1-9]|1[012])\/\d{4}/m
str = '2020
2019/10/16
2020/08/12
31/01/2020
2020-11-03
05/01/2020
04/17/2020
2019/12/31
2021-07-14
2019/12/04
2010/12/16
2021
04/03/2020
4/30/2020
2011/07/18
2017/06/20
2019
2021-10-13
2020
2021-07-14
2021/11/08
2020-11-03
2021
2019/12/31
2019-12-04
null
2020/01/04'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html