re = /^(0|[1-9]+[0-9]*) (@[^@]+@ |)([A-Za-z0-9_]+)( [^\n\r]*|)$/m
str = '0 @N1@ NOTE Lorem ipsum dolor sit amet
0 HEAD
1 SOUR FTM
2 VERS 22.2.6.950
1 DEST FTM
1 DATE 31 MAR 2017
1 CHAR UTF-8
3 _LINK http://www.facebook.com/1247584965
2 SOUR @S122@
3 PAGE Facebook update - David Hatch - 6/5/2013
3 _LINK http://www.facebook.com/1247584965
1 RESI
2 DATE BET 1935 AND 1993
2 PLAC San Francisco, California, USA
1 RESI
2 DATE 1994
2 PLAC San Francisco, California, USA
2 SOUR @S605@
3 DATA
4 TEXT Birth date: 20 Sep 1966 Birth place: Residence date: 1994
5 CONC Residence place: San Francisco, CA
1 RESI 106 Oakcrest Rd
2 DATE 26 MAR 2017
2 PLAC San Anselmo, Marin, California, USA
1 FAMS @F500@
1 FAMC @F656@
0 @I923@ INDI
1 NAME Vincent /Crilley/
1 SEX M
1 FAMS @F254@
0 @I5899@ INDI
1 NAME Marjorie Edna /Footitt/
2 SOUR @S506@
2 SOUR @S176@
2 SOUR @S168@
2 SOUR @S624@
3 DATA
4 TEXT Residence date: Residence place: USA
2 SOUR @S115@
3 PAGE Year: 1940; Census Place: St Paul, Ramsey, Minnesota; Roll: T627_1996;
4 CONC Page: 11A; Enumeration District: 90-73.
3 DATA
4 _TEXT Birth date: abt 1918 Birth place: North Dakota Residence date: 1
5 CONC Apr 1940 Residence place: St Paul, Ramsey, Minnesota, United States
2 SOUR @S607@
3 PAGE Year: 1920; Census Place: Carrington, Foster, North Dakota; Roll:
4 CONC T625_1334; Page: 13B; Enumeration District: 117; Image: .
3 DATA'
subst = '\\n2($2) 3($3) 4($4) 5($5) 6($6) 7($7) \\n\\n8($8) 9($9) 10($10) 11($11) 12($12) 13($13) 14($14) 15($15) 16($16) 18($18) 20($20) 21($21)\\n\\n\\n\\n'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html