using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"([""])(?:(?!\1|"").|"".)*\1";
string substitution = @"Subbed";
string input = @"Hello Colm ""This is a test""\\""
""This is also an NL test""
'And this has an escaped quote don\'t in it ' Blue Boy
""This has a single quote ' but doesn\' end the quote as it started with double quotes""
""""line spanning with escaped quote at the end of a line""""
""""
""Foo Bar"" ""Another Value"" something else";
Regex regex = new Regex(pattern);
string result = regex.Replace(input, substitution);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx