import Foundation
let pattern = #"^\s*Processo\s*\d{7}\-\d{2}\.\d{4}\.\d\.\d{2}\.\d{4}\,"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
PROCESSO :1000069-51.2019.8.26.0486
Processo 0000508-21.2015.8.26.0486
Processo 0010464-93.2018.8.26.0506/02
Processo 0022276-35.2018.8.26.0506/562
Nº 0000002-25.2019.8.26.9048
540.423 -
1.125.553 -
NPE 950.128
PEC 910.494
NPE 1.177.941
EXPEDIENTE AVULSO - NPE 1.089.733
EXECUÇÃO: 699.764
EXECUÇÃO: 1.101.909
CPPJ 12/2013 E 64/2013
1. EXECUÇÃO Nº 629.142
2. EXECUÇÃO Nº 1.013.657
PROTOCOLO Nº 543 FSBL 1800017858-9
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression