import Foundation
let pattern = #"^([A-Z][AEIOUX][A-Z]{2}\d{2}(?:0[1-9]|1[0-2])(?:0[1-9][12]\d|3[01])[HM](?:AS|B[CS]|C[CLMSH]|D[FG]|G[TR]|HG|JC|M[CNS]|N[ETL]|OC|PL|Q[TR]|S[PLR]|T[CSL]|VZ|YN|ZS)[B-DF-HJ-NP-TV-Z]{3}[A-Z\d])(\d)$"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"RICJ750331HDFVMN04"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression