import Foundation
let pattern = #"(?<AMEX>3[47]\d\d[\s\-]?(?!(\d)\2{5}|123456|234567|345678)\d{6}[\s\-]?(?!(\d)[\s\-]{4}|12345|56789)\d{5})|(?<MASTERCARD>5[1-5]\d{2}[\s\-]?\d{4}[\s\-]?\d{4}[\s\-]?\d{4})|(?<VISA>4\d{3}[\s\-]?(?:\d{4}[\s\-]?){2}\d(?:\d{3})?)|(?<DISCOVER>6(?:011|22?=[\s\-]?[6-9]|[3-9]|[2-8]|9[\s\-]?[01]|2[0-5]|4[4-9]\d|5\d\d)[\s\-]?\d{4}[\s\-]?\d{4}[\s\-]?\d{4})"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression