import Foundation
let pattern = #"^(?<sexe>[1-478])\s*?(?<annee>[0-9]{2})\s*?(?<mois>0[1-9]|1[0-2]|[2-3][0-9]|4[0-2]|[5-9][0-9])\s*?(?<departement>2[ABab]|[0-9]{2}|9[7-8][0-9])\s*?(?<commune>[0-9]{3}|[0-9]{2})\s*?(?<ordre>00[1-9]|0[1-9][0-9]|[1-9][0-9]{2})\s*?(?<cle>0[1-9]|[1-8][0-9]|9[0-7])\s*?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
100089932132111
2 80 05 17 001 001 01
Cas Spécifiques définis ici : https://fr.wikipedia.org/wiki/Num%C3%A9ro_de_s%C3%A9curit%C3%A9_sociale_en_France
=> Naissance à l'étranger en cours d'immatriculation en France avec mois de naissance pseudo-fictif (état-civil incomplet)
8 00 31 99 901 001 02
=> Naissance en Outre-Mer
2 00 01 987 01 001 02
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression