import Foundation
let pattern = #"\b(0?[1-9]|[12]\d|3[01])[\/\-.](0?[1-9]|[12]\d|3[01])[\/\-.](\d{2}|\d{4})\b"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
Bắt các chuỗi ngày tháng này
12/01/2017
15/2/2017
3/03/2018
12/24/2018
1.1.2018
7-9-18
1.31.2018
Không bắt các chuỗi như thế này, vì không đúng ngày tháng
123/2/1234 13/ab/3346 12/223/12 60/60/2018 32/12/2018
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression