import Foundation
let pattern = #"((?:(25[0-5]|2[0-4]\d|1\d\d|[1-9]\d|\d)\.){3}(?-1))"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
Feb 8 21:48:20 server dhcpd: DHCPREQUEST for 10.232.10.241 (10.232.10.241) from 24:77:03:18:c9:d4 (kimxlt-03) via eth1
Feb 8 21:48:20 server dhcpd: DHCPACK on 10.232.10.76 to 24:77:03:18:c9:d4 (kimxlt-03) via eth1
Feb 8 21:48:24 server dhcpd: DHCPINFORM from 10.232.10.76 via eth1
Feb 8 21:48:24 server dhcpd: DHCPACK to 10.232.10.76 (24:77:03:18:c9:d4) via eth1
Feb 8 21:50:31 server dhcpd: DHCPINFORM from 10.232.10.92 via eth18 21:50:31 server dhcpd: DHCPACK to 10.232.10.92 (00:1c:c0:58:85:1b) via eth1
Feb 8 21:55:44 server dhcpd: DHCPINFORM from 10.232.10.92 via eth1
Feb 8 21:55:44 server dhcpd: DHCPACK to 10.232.10.92 (00:1c:c0:58:85:1b) via eth1
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression