import Foundation
let pattern = #"\b(?:(?:0?[0-9]?[0-9]|1?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])\.??\b){4}"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Should Match:
204.131.100.104
255.255.005.055
192.168.10.1
172.16.1.1
10.10.10.1
1.2.3.4
255.255.255.255
001.02.3.004
123.145.254.189:8080
1.2.3.4-4.3.20.1
4.3.2.1.9.8.7.6
Shouldnt match:
255.256.255.255
172.999.2.3
this is a string1.2.3.4
this is another 1.2.3.4string
144.109.279.255
v1.2.3.4
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression