import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "[2][0-9][0-9][0-9]\\/[0-9][[0-9]\\/";
final String string = "161 1 2015/12/17 14:52:08:44648 13668 38528 1 *** 15 5 CDF_ENTRY [Id=1] hook_MFCreateSourceResolver: Entering. \n"
+ "162 1 2015/12/17 14:52:08:44664 13668 38528 1 *** 15 5 CDF_ENTRY [Id=2] SourceResolverWrapper::FinalConstruct: Entering. \n"
+ "163 1 2015/12/17 14:52:08:44664 13668 38528 1 *** 20 5 CDF_ENTRY [Id=2] SourceResolverWrapper::FinalConstruct: Leaving. (hr=0x0) \n"
+ "164 1 2015/12/17 14:52:08:44665 13668 38528 1 *** 20 5 CDF_ENTRY [Id=1] hook_MFCreateSourceResolver: Leaving. (hr=0x0) \n"
+ "165 1 2015/12/17 14:52:08:44666 13668 38528 1 *** 15 5 CDF_ENTRY [Id=2] SourceResolverWrapper::BeginCreateObjectFromURL: Entering. ";
final String subst = "2016/01/";
final Pattern pattern = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceFirst(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html