import Foundation
let pattern = #"([+]\d{1,2}|(00)\d{2,4}|\d{2})( [(]\d{1,3}[)])?[-. \/]?\d{2,6}?[-. \/]?\d{2,15}([-. \/]{1,3}\d{1,5}){0,4}"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .dotMatchesLineSeparators])
let testString = #"""
+49 40 123456-0
+49 40 123456 -0
+49 40 123456- 0
0049 40 123456-0
49 40 3339760
+49 151 1234 56 78
+49 40123456 - 282
+49 40 123 456 -282
0049 40 123 456 -282
+49 40 123456 - 282
+49 (0)40 123456-282
+49 (0) 40 123456 -282
+49 (0) 40 12 34 56 -282
0049 (0) 40 123456 -282
49 (0) 40 123456 -282
+4940123456282
0049401234560
+1-234-567-8901
+61-234-567-89-01
+46-234 5678901
+1 (234) 56 89 901
+1 (234) 56-89 901
+46.234.567.8901
+1/234/567/8901
Wenn man mich fragen würde, ob ich unter der +49 40 123456 282 erreichbar bin, würde ich sagen. "JA"
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression