import Foundation
let pattern = #"""
(?<!\d)
(?:
(?!0000)[0-9]{4}
(?P<sep1>[-/.])?
(?:
(?:(?(sep1)0?|0)[1-9]|1[0-2]) (?P=sep1) (?:(?(sep1)0?|0)[1-9]|1[0-9]|2[0-8])
|(?:(?(sep1)0?|0)[13-9]|1[0-2]) (?P=sep1) (?:29|30)
|(?:(?(sep1)0?|0)[13578]|1[02]) (?P=sep1) (?:31)
)
|
(?:
[0-9]{2}
(?:
0[48]
|[2468][048]
|[13579][26]
)
|(?:
0[48]
|[2468][048]
|[13579][26]
)00
)
(?P<sep2>[-/.]?)
(?(sep2)0?|0)2 (?P=sep2) (?:29)
)
(?!\d)
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .allowCommentsAndWhitespace])
let testString = #"""
aaa_20150229_bbb
aaa_2012-02-29_bbb
aaa_2000-02-29_bbb
aaa_20000229_bbb
2004-2-29
1696-2-29
16960229
aaa_1904229_bbb
aaa_18000229_bbb
aaa_17000229_bbb
aaa_16000229_bbb
2019-3-30
19960229
aaa_20150130_bbb
aaa_20150131_bbb
aaa_2015-04-30_bbb
aaa_20150431_bbb
2019228
2019228
201911
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression