import Foundation
let pattern = #"^AL\d{10}[0-9A-Z]{16}$|^AD\d{10}[0-9A-Z]{12}$|^AT\d{18}$|^BH\d{2}[A-Z]{4}[0-9A-Z]{14}$|^BE\d{14}$|^BA\d{18}$|^BG\d{2}[A-Z]{4}\d{6}[0-9A-Z]{8}$|^HR\d{19}$|^CY\d{10}[0-9A-Z]{16}$|^CZ\d{22}$|^DK\d{16}$|^FO\d{16}$|^GL\d{16}$|^DO\d{2}[0-9A-Z]{4}\d{20}$|^EE\d{18}$|^FI\d{16}$|^FR\d{12}[0-9A-Z]{11}\d{2}$|^GE\d{2}[A-Z]{2}\d{16}$|^DE\d{20}$|^GI\d{2}[A-Z]{4}[0-9A-Z]{15}$|^GR\d{9}[0-9A-Z]{16}$|^HU\d{26}$|^IS\d{24}$|^IE\d{2}[A-Z]{4}\d{14}$|^IL\d{21}$|^IT\d{2}[A-Z]\d{10}[0-9A-Z]{12}$|^[A-Z]{2}\d{5}[0-9A-Z]{13}$|^KW\d{2}[A-Z]{4}22!$|^LV\d{2}[A-Z]{4}[0-9A-Z]{13}$|^LB\d{6}[0-9A-Z]{20}$|^LI\d{7}[0-9A-Z]{12}$|^LT\d{18}$|^LU\d{5}[0-9A-Z]{13}$|^MK\d{5}[0-9A-Z]{10}\d{2}$|^MT\d{2}[A-Z]{4}\d{5}[0-9A-Z]{18}$|^MR13\d{23}$|^MU\d{2}[A-Z]{4}\d{19}[A-Z]{3}$|^MC\d{12}[0-9A-Z]{11}\d{2}$|^ME\d{20}$|^NL\d{2}[A-Z]{4}\d{10}$|^NO\d{13}$|^PL\d{10}[0-9A-Z]{,16}n$|^PT\d{23}$|^RO\d{2}[A-Z]{4}[0-9A-Z]{16}$|^SM\d{2}[A-Z]\d{10}[0-9A-Z]{12}$|^SA\d{4}[0-9A-Z]{18}$|^RS\d{20}$|^SK\d{22}$|^SI\d{17}$|^ES\d{22}$|^SE\d{22}$|^CH\d{7}[0-9A-Z]{12}$|^TN59\d{20}$|^TR\d{7}[0-9A-Z]{17}$|^AE\d{21}$|^GB\d{2}[A-Z]{4}\d{14}$"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"NL39INGB0044332211"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
if let firstMatch = regex.firstMatch(in: testString, range: stringRange) {
let result: [String] = (1 ..< firstMatch.numberOfRanges).map { (testString as NSString).substring(with: firstMatch.range(at: $0)) }
print(result)
} else {
print("No matches were found.")
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression