import Foundation
let pattern = #"(?<=[\s\.\,\!\?\"\;\:]|^)(?=[A-Za-z']*?[bcdfghj-np-tvwxyzBCDFGHJ-NP-TVWXYZ])(?=[A-Za-z']*?[aeiouyAEIOUY'])(?:[A-Za-z](?:'?[A-Za-z]){2}|(?:'?[A-Za-z]){2}[A-Za-z])\b'?(?=[\s\.\,\!\?\"\;\:]|$)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
This regex matches any three letter string that has at least one vowel and at least one consonant. As you can see, it's very effective and it only matches 3 letter words.
The word "I'll" should count as a 3 letter word. Words like "isn't," "you'dn't've," and "let's" shouldn't. Jo's dog is smart. The quick brown dog jumped over the lazy fox.
The qis' house. "qis'" is just a made up word to test stuff like "kids'" but for 3 letters.
asd
'asd
a'sd
as'd
asd'
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression