import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "\\#(.*?)\\*\\*(.*?)\\*\\*";
final String string = "Here’s an extended version of the previous explanation, now including **problem definitions**, **approaches**, and **examples** for each interval problem:\n\n"
+ "---\n\n"
+ "### 1. **Basic Interval Problems**\n\n"
+ "#### a) **Finding Overlaps Between Two Intervals**\n\n"
+ "- **Problem Definition**: Given two intervals, determine if they overlap. Two intervals overlap if they share at least one point in common.\n"
+ " \n"
+ "- **Approach**: \n"
+ " - Check if the start of one interval is before the end of the other and vice versa.\n"
+ " \n"
+ "- **Example**: \n"
+ " - Interval A = [1, 5], Interval B = [4, 9].\n"
+ " - Output: True (they overlap).\n\n"
+ "```python\n"
+ "def do_intervals_overlap(interval1, interval2):\n"
+ " return interval1[0] <= interval2[1] and interval2[0] <= interval1[1]\n\n"
+ "# Example\n"
+ "interval1 = [1, 5]\n"
+ "interval2 = [4, 9]\n"
+ "print(do_intervals_overlap(interval1, interval2)) # True\n"
+ "```\n\n"
+ "#### b) **Union of Two Intervals**\n\n"
+ "- **Problem Definition**: Given two intervals, return the union of the intervals if they overlap or are adjacent. If they do not overlap, return both intervals.\n\n"
+ "- **Approach**: \n"
+ " - If the intervals overlap, return the minimum start and maximum end of the two intervals.\n\n"
+ "- **Example**: \n"
+ " - Interval A = [1, 5], Interval B = [4, 9].\n"
+ " - Output: [1, 9].\n\n"
+ "```python\n"
+ "def union_intervals(interval1, interval2):\n"
+ " if do_intervals_overlap(interval1, interval2):\n"
+ " return [min(interval1[0], interval2[0]), max(interval1[1], interval2[1])]\n"
+ " return [interval1, interval2]\n\n"
+ "# Example\n"
+ "print(union_intervals([1, 5], [4, 9])) # [1, 9]\n"
+ "```\n\n"
+ "#### c) **Intersection of Two Intervals**\n\n"
+ "- **Problem Definition**: Find the intersection of two intervals. The intersection is the range that is covered by both intervals.\n\n"
+ "- **Approach**: \n"
+ " - If the intervals overlap, the intersection is the maximum of the start points and the minimum of the end points.\n\n"
+ "- **Example**: \n"
+ " - Interval A = [1, 5], Interval B = [3, 9].\n"
+ " - Output: [3, 5].\n\n"
+ "```python\n"
+ "def intersection_intervals(interval1, interval2):\n"
+ " if do_intervals_overlap(interval1, interval2):\n"
+ " return [max(interval1[0], interval2[0]), min(interval1[1], interval2[1])]\n"
+ " return None\n\n"
+ "# Example\n"
+ "print(intersection_intervals([1, 5], [3, 9])) # [3, 5]\n"
+ "```\n\n"
+ "---\n\n"
+ "### 2. **Multiple Intervals Problems**\n\n"
+ "#### a) **Merging Overlapping Intervals**\n\n"
+ "- **Problem Definition**: Given a set of intervals, merge all the overlapping ones.\n\n"
+ "- **Approach**: \n"
+ " - Sort the intervals by their start time, then iterate through them and merge overlapping intervals.\n\n"
+ "- **Example**: \n"
+ " - Intervals = [[1, 5], [2, 6], [8, 10]].\n"
+ " - Output: [[1, 6], [8, 10]].\n\n"
+ "```python\n"
+ "def merge_intervals(intervals):\n"
+ " intervals.sort(key=lambda x: x[0])\n"
+ " merged = [intervals[0]]\n"
+ " \n"
+ " for i in range(1, len(intervals)):\n"
+ " if merged[-1][1] >= intervals[i][0]:\n"
+ " merged[-1][1] = max(merged[-1][1], intervals[i][1])\n"
+ " else:\n"
+ " merged.append(intervals[i])\n"
+ " \n"
+ " return merged\n\n"
+ "# Example\n"
+ "print(merge_intervals([[1, 5], [2, 6], [8, 10]])) # [[1, 6], [8, 10]]\n"
+ "```\n\n"
+ "#### b) **Finding Gaps Between Intervals**\n\n"
+ "- **Problem Definition**: Given a set of intervals, find the gaps where no interval exists.\n\n"
+ "- **Approach**: \n"
+ " - Sort intervals by start time. Identify gaps by checking the end of one interval and the start of the next.\n\n"
+ "- **Example**: \n"
+ " - Intervals = [[1, 5], [7, 10]].\n"
+ " - Output: [5, 7].\n\n"
+ "```python\n"
+ "def find_gaps(intervals):\n"
+ " intervals.sort(key=lambda x: x[0])\n"
+ " gaps = []\n"
+ " \n"
+ " for i in range(1, len(intervals)):\n"
+ " if intervals[i][0] > intervals[i-1][1]:\n"
+ " gaps.append([intervals[i-1][1], intervals[i][0]])\n"
+ " \n"
+ " return gaps\n\n"
+ "# Example\n"
+ "print(find_gaps([[1, 5], [7, 10]])) # [[5, 7]]\n"
+ "```\n\n"
+ "---\n\n"
+ "### 3. **Complex Interval Operations**\n\n"
+ "#### a) **Interval Difference**\n\n"
+ "- **Problem Definition**: Given two intervals, find the difference between them, i.e., the part of the first interval that does not overlap with the second.\n\n"
+ "- **Approach**: \n"
+ " - If the intervals overlap, return the non-overlapping portions of the first interval.\n\n"
+ "- **Example**: \n"
+ " - Interval A = [1, 10], Interval B = [5, 7].\n"
+ " - Output: [[1, 5], [7, 10]].\n\n"
+ "```python\n"
+ "def interval_difference(A, B):\n"
+ " if not do_intervals_overlap(A, B):\n"
+ " return [A] # No overlap\n"
+ " \n"
+ " result = []\n"
+ " if A[0] < B[0]:\n"
+ " result.append([A[0], B[0]])\n"
+ " if A[1] > B[1]:\n"
+ " result.append([B[1], A[1]])\n"
+ " \n"
+ " return result\n\n"
+ "# Example\n"
+ "print(interval_difference([1, 10], [5, 7])) # [[1, 5], [7, 10]]\n"
+ "```\n\n"
+ "#### b) **Interval Scheduling**\n\n"
+ "- **Problem Definition**: Given a set of intervals, find the maximum number of non-overlapping intervals that can be selected.\n\n"
+ "- **Approach**: \n"
+ " - Sort intervals by end time. Greedily select intervals that do not overlap with the previously selected one.\n\n"
+ "- **Example**: \n"
+ " - Intervals = [[1, 3], [2, 4], [3, 5]].\n"
+ " - Output: [[1, 3], [3, 5]].\n\n"
+ "```python\n"
+ "def interval_scheduling(intervals):\n"
+ " intervals.sort(key=lambda x: x[1]) # Sort by end times\n"
+ " result = []\n"
+ " last_end = float('-inf')\n"
+ " \n"
+ " for interval in intervals:\n"
+ " if interval[0] >= last_end:\n"
+ " result.append(interval)\n"
+ " last_end = interval[1]\n"
+ " \n"
+ " return result\n\n"
+ "# Example\n"
+ "print(interval_scheduling([[1, 3], [2, 4], [3, 5]])) # [[1, 3], [3, 5]]\n"
+ "```\n\n"
+ "---\n\n"
+ "### 4. **Advanced Interval Challenges**\n\n"
+ "#### a) **Finding the Smallest Range Covering All Points**\n\n"
+ "- **Problem Definition**: Given several lists of intervals, find the smallest range that includes at least one interval from each list.\n\n"
+ "- **Approach**: \n"
+ " - Use a sliding window and min-heap to track the smallest range covering all lists.\n\n"
+ "- **Example**: \n"
+ " - Lists = [[1, 5], [6, 9], [7, 10]].\n"
+ " - Output: (6, 7).\n\n"
+ "```python\n"
+ "import heapq\n\n"
+ "def smallest_range(lists):\n"
+ " min_heap = []\n"
+ " max_val = float('-inf')\n"
+ " \n"
+ " # Add the first element of each list to the heap\n"
+ " for i, l in enumerate(lists):\n"
+ " heapq.heappush(min_heap, (l[0], i, 0))\n"
+ " max_val = max(max_val, l[0])\n"
+ " \n"
+ " min_range = float('inf'), None, None\n"
+ " \n"
+ " while min_heap:\n"
+ " min_val, list_idx, element_idx = heapq.heappop(min_heap)\n"
+ " if max_val - min_val < min_range[0]:\n"
+ " min_range = (max_val - min_val, min_val, max_val)\n"
+ " \n"
+ " if element_idx + 1 == len(lists[list_idx]):\n"
+ " break # We've reached the end of one list\n"
+ " \n"
+ " next_val = lists[list_idx][element_idx + 1]\n"
+ " max_val = max(max_val, next_val)\n"
+ " heapq.heappush(min_heap, (next_val, list_idx, element_idx + 1))\n"
+ " \n"
+ " return min_range[1], min_range[2]\n\n"
+ "# Example\n"
+ "lists = [[1, 5], [6, 9], [7, 10]]\n"
+ "print(smallest_range(lists)) # (6, 7)\n"
+ "```\n\n"
+ "#### b) **K-Interval Coverage**\n\n"
+ "- **Problem Definition**: Given a set of intervals and an integer `k`, find the maximum number of intervals that cover any point or range.\n\n"
+ "- **Approach**: \n"
+ " - Sort events (start and end of intervals), track the number of overlapping intervals at each event, and find the maximum count.\n\n"
+ "- **Example**: \n"
+ " - Intervals = [[1, 4], [2, 6], [3, 8]], k = 2.\n"
+ " - Output: 2.\n\n"
+ "```python\n"
+ "def max_k_interval_coverage(intervals, k):\n"
+ " points = []\n"
+ " for interval in intervals:\n"
+ " points.append((\n\n"
+ "interval[0], 'start'))\n"
+ " points.append((interval[1], 'end'))\n"
+ " \n"
+ " points.sort()\n"
+ " coverage = 0\n"
+ " max_coverage = 0\n"
+ " \n"
+ " for point, kind in points:\n"
+ " if kind == 'start':\n"
+ " coverage += 1\n"
+ " if coverage == k:\n"
+ " max_coverage = max(max_coverage, coverage)\n"
+ " else:\n"
+ " coverage -= 1\n"
+ " \n"
+ " return max_coverage\n\n"
+ "# Example\n"
+ "print(max_k_interval_coverage([[1, 4], [2, 6], [3, 8]], 2)) # 2\n"
+ "```\n\n"
+ "---\n\n"
+ "### 5. **Geometric Interval Problems**\n\n"
+ "#### a) **Rectangle Intersection via Intervals**\n\n"
+ "- **Problem Definition**: Given two rectangles, where each rectangle is defined by two intervals (x-axis and y-axis), find the intersection of these rectangles.\n\n"
+ "- **Approach**: \n"
+ " - Find the intersection of intervals on both x and y axes. The intersection of two rectangles is the combination of the intersecting intervals on both axes.\n\n"
+ "- **Example**: \n"
+ " - Rectangle A = ([1, 5], [2, 6]), Rectangle B = ([3, 7], [4, 9]).\n"
+ " - Output: [[3, 5], [4, 6]].\n\n"
+ "```python\n"
+ "def rectangle_intersection(A, B):\n"
+ " x_intersect = intersection_intervals([A[0][0], A[0][1]], [B[0][0], B[0][1]])\n"
+ " y_intersect = intersection_intervals([A[1][0], A[1][1]], [B[1][0], B[1][1]])\n"
+ " \n"
+ " if x_intersect and y_intersect:\n"
+ " return [x_intersect, y_intersect]\n"
+ " return None\n\n"
+ "# Example\n"
+ "A = ([1, 5], [2, 6])\n"
+ "B = ([3, 7], [4, 9])\n"
+ "print(rectangle_intersection(A, B)) # [[3, 5], [4, 6]]\n"
+ "```\n\n"
+ "---\n\n"
+ "This version includes **problem definitions**, **approaches**, and **examples** for all the interval problems, along with code implementations. Each section is structured to make it easier to understand and apply to similar problems.";
final String subst = "\\#\\1\\2";
final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);
// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);
System.out.println("Substitution result: " + result);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html