import Foundation
let pattern = #"^([0-9a-f]{1,4}:)+(([0-9a-f]{1,4})?:)+([0-9a-f]{1,4})(?= )"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
2a03:2880:30ff:4::face:b00c --
2600:387:f:4533::8 - -
2600:387:5:805::84 - -
2a02:120b:2c12:df00:bc9f:adfd:eac6:4011 - -
2601:602:8b00:e50::c1f0 - -
2409:4042:112:8a7b::27bd:70b1 - -
2603:7000:a803:beb2:e0c0:3f:2a1b:5d60 - -
::1 - -
:a:1 - -
:bh:lh:1 - -
1:1:fEd1:1:abdc:1 - -
::ffff:192.0.2.128 - -
0000:0000:0000:0000:0000:0000:0000:0001 - -
2001:0db8:0000:0000:0000:ff00:0042:8329 - -
2001:db8:0:0:0:ff00:42:8329 - -
2001:db8::ff00:42:8329 - -
2001:0db8:0000:0000:0000:ff00:0042:8329 - -
2a03:2880:30ff:4::face:b00c --
2600:387:f:4533::8 - -
2600:387:5:805::84 - -
2a02:120b:2c12:df00:bc9f:adfd:eac6:4011 - -
2600:387:0:80f::4a - -
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression