# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"^(?:\+44\s?|0)[1238]\d\s?(?:\d\s?){7,8}$"
test_str = ("# Standard\n"
"01386 444400\n"
"01386444400\n"
"+441386444400\n"
"+44 1386 444400\n"
"+44 1386444400\n\n"
"# 5 Digit\n"
"01386 41204\n"
"0138641204\n"
"+44138641204\n"
"+44 1386 41204\n"
"+44 138641204\n\n"
"# 3 Digit area codes (e.g. London)\n"
"+442074343046\n"
"02074343046\n"
"020 74343046\n"
"020 7434 3046\n\n"
"# 4 Digit area codes (e.g. Leeds)\n"
"+441133971337\n"
"01133971337\n"
"0113 3971337\n\n"
"# Commercial\n"
"08451772266\n"
"0845 1772266\n\n"
"# Mobile number (should not match)\n"
"07999888777\n"
"+447999888777\n"
"07999 888 777\n"
"+44 7999888777\n")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html