re = /([A-Z]{3})(20\d{2})(\d{9})\b/
str = 'PRK2017000003021
PRK2017000003017
AAA2017000000000
aaa2017956639163
Aaa2017956639163
AAa2017956639163
aAA2017956639163
DMY2017817027421
PRK2017000003022
PRK2017000003023
PRN2017000000001
IHR2018000000001
IHR2018000000002
IHR2018000000003a
DMY20180112150945'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html