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Given a string, the regex would match if it is a valid IPv4 address.

help please. i need regex,

This search for special character at first position in the string

Used with Java regexp. F.e. you can use replaceAll("regexp", "filePath").

Grep the daily purchase price for 250 g gold from http://www.scheideanstalt.de/aktuelle-ankaufskurse/ankaufskurse-barren/: gold=$(wget -q -O- http://www.scheideanstalt.de/aktuelle-ankaufskurse/ankaufskurse-barren/ | grep "250 g" | sed -r 's/^.250 g]>([0-9]+)\.([0-9]+[0-9]+[0-9]+)\,([0-9]+[0-9]+).*$...

If needed to test entered website

email validation based on the restrictions for entering email adresses into a mongo db email field.

Validates all possible international phone number formats. Icludes almoust all of the international call prefixes, all of the differing lenghts of country codes. The parts of number will always be recognised correctly. Additionally you could add limitations of the phone number's lenght

The given regex matches the IPV4 address of given ip address string.

Matches the following format of US address: Street, City, State|State Code, Zip Example: 765757 North Nevada Avenue, Colorado Springs, CO, 80918

Matches all ips that points to localhost like, optionally capturing port number: 127.X.X.X and 127.X.X.X:

Validates the format of IPv4/IPv6 hostnames as well as domain names.