身份证号(2代,18位数字),最后一位是校验位,可能为数字或字符X

身份证号, 支持1/2代(15位/18位数字)

Comprehensively matches every possible pre-name player title in discworldmud. http://discworld.starturtle.net/lpc/ https://dwwiki.mooo.com/wiki/Title

Date Match

Matching Same Text Again & Again

PCRE Regular expression that validates JSON according to grammar specified at RFC-8259 (https://tools.ietf.org/html/rfc8259)

Based on an expression from haacked.com

Using a Non-capturing Group: regex + python This question was asked on stackoverflow and it appeared that the best way to match the expression will be to use a non-capturing group. [#so-question]: https://stackoverflow.com/questions/61882072/python-regex-findall-function-only-returning-matchings-o...

I figured this would be the simplest way to Parse JSON. We have some known information about the properties to help determine the type at runtime. Properties - Immediately followed by : characters Values - Have a bracket } ] or a , directly after it in the regex return. Strings - They are surrounded...

Matches: integers [+-]?\d+(Ee?\d+)? like +45 or 96E-3 or -12e+24 floats starting from "." or "," like -.45e-3 floats starting from \d like 3.14 or -0.67E12

'string in simple quotes' "in double-quotes" in back-quotes "Works good with symbols ' or " or ` inside the string" "All another type quotes "' inside string are ignored" use something like \ or \" or \' " Matches only identical quotes on string start and end ' // regex can`t find this...

Notes: Do not forget to escape the $ by an additional $. Escaping ? like \? does not work. But you could use [?] instead End result should be like this: "traefik.http.middlewares.r6tt-dev-web.stripprefixregex.regex=^/[a-z0-9/]+[a-z0-9]+([?]+.*)?$$"...

Used this to dynamically create placeholder text when a user changed the coordinates format from default to custom. ex ['DD', 'DDM', 'DMS'] to remove the comma from the string. The format comes from an array of strings so I had to do a join(', ').replace(/\,(?=*$)/g, ' or') to get DD, DDM or DMS